ऊर्जा की खपत =250 kWh 1 kWh = 3.6 x 106 J
∴ 250 ऊर्जा की खपत = 250 x 3.6 x 106 = 9 x 108 J.
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NCERT solutions for class 8 9 10 11 12. Find NCERT textbook questions and answers for cbse Class class 8 9 10 11 12.
Answer :- Adivasis
by using half life equation, we getK = 0.693t1/2K = 0.69330 min = 0.0231 at 27°C or 300 KK = 0.69310 min = 0.0693 at 47°C or 320 KFrom the Arrhenius equationlogk2k1 = Ea2.3031T1-T2 Ea = 2.303×R×T1×T2T2-T1log k2k1= 2.303 × 8.314 J K-1 mol-1×300×320 K320 K - 300 K log 0.06935-10.02315-1 = 43.848 kJ mol-1.
In the figure given, the tangent to the circular ring in the plane of the ring is shown. Let, the tangent be represented by XY and diameter be represented by AB. Using the theorem of parallel axes, we have IXY = IAB + M (R)2 = i.e., IXY = Therefore, the moment of inertia of ring about tangent in the plane of the ring is 3/2 MR2.
Textbook solutions for class 9 10 11 12. Find textbook questions and answers for gsebe class eighth, ninth, tenth, eleventh, twelfth online.
We have x2 – 5x + 6 – x2 – 3x – 2x + 6= (x – 3) (x – 2)So, the value of x2 – 5x + 6 is zero when x - 3 = 0 or x – 2 = 0i.e., when x = 3 or x = 2Therefore, the zeroes of x2 – 5x + 6 are 3 and 2.Sum of zeroes = = Product of zeroes
(a)
(i) Propanone to Propan-2-ol
(ii) Ethanal to 2-Hydroxypropanoic acid
(iii) Toluene to benzoic acid.
(b)
(i) Pentan-2-one and Pentan-3-one
By Iodoform Test
Pentan-2-one being a methyl ketone when treated with NaOI (I2/NaOH) gives yellow precipitate of iodoform but pentan-3-one does not.
(ii) Ethanal and Propanal
By Iodoform test
Ethanal containing group CH3-C=O linked to H, reacts with I2/NaOH (or NaOI) to give yellow precipitate of iodoform but propanal does not contain group CH3-C=O linked to H or C and hence does not react with I2/NaOH to
(i) Propanone to Propan-2-ol
(ii) Ethanal to 2-Hydroxypropanoic acid
(iii) Toluene to benzoic acid.
(b)
(i) Pentan-2-one and Pentan-3-one
By Iodoform Test
Pentan-2-one being a methyl ketone when treated with NaOI (I2/NaOH) gives yellow precipitate of iodoform but pentan-3-one does not.
(ii) Ethanal and Propanal
By Iodoform test
Ethanal containing group CH3-C=O linked to H, reacts with I2/NaOH (or NaOI) to give yellow precipitate of iodoform but propanal does not contain group CH3-C=O linked to H or C and hence does not react with I2/NaOH to
Here P = Rs 8000, T = 1 year, R = 9% p.a.Interest is compounded half yearly,∴ T = 1 year = 2 half years R = 9% p.a.= half yearly
∵ Amount = = Rs 8000 = Rs. = Rs CI = Rs 8736.20 - Rs 8000 = Rs 736.20
∵ Amount = = Rs 8000 = Rs. = Rs CI = Rs 8736.20 - Rs 8000 = Rs 736.20
? = 40 x12 + 3 - 6÷60On changign the signs,? = 40 + 12 ÷ 3 x 6 - 60? = 40 + 4 x 6-60? = 40 + 24 - 60? = 64-60 = 4? = 4
Any process in which no heat is allowed to be exchanged with surroundings is called an adiabatic process. Essential conditions for the adiabatic process to take place are: i) System is perfectly insulated from surrounding. ii) The process must be carried out rapidly so that the system hs sufficient time to exchange heat with the surroundings.
i) De-broglie wavelength ( of moving particles varies with their linear momentum (p).De-broglie wavelength varies inversely proportional with the linear momentum.ii) In interference, the moving particles exhibit wave nature.